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2.8+7.2x-10x^2=0
a = -10; b = 7.2; c = +2.8;
Δ = b2-4ac
Δ = 7.22-4·(-10)·2.8
Δ = 163.84
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7.2)-\sqrt{163.84}}{2*-10}=\frac{-7.2-\sqrt{163.84}}{-20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7.2)+\sqrt{163.84}}{2*-10}=\frac{-7.2+\sqrt{163.84}}{-20} $
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